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245=1/2x^2
We move all terms to the left:
245-(1/2x^2)=0
Domain of the equation: 2x^2)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
-1/2x^2+245=0
We multiply all the terms by the denominator
245*2x^2-1=0
Wy multiply elements
490x^2-1=0
a = 490; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·490·(-1)
Δ = 1960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1960}=\sqrt{196*10}=\sqrt{196}*\sqrt{10}=14\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{10}}{2*490}=\frac{0-14\sqrt{10}}{980} =-\frac{14\sqrt{10}}{980} =-\frac{\sqrt{10}}{70} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{10}}{2*490}=\frac{0+14\sqrt{10}}{980} =\frac{14\sqrt{10}}{980} =\frac{\sqrt{10}}{70} $
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